this post was submitted on 27 Nov 2025
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Science Memes

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[–] Triasha@lemmy.world 78 points 1 month ago (5 children)

Pemdas, parenthesis first, for a total of 3. Then multiplication, 15, then addition. 17. What's hard about this?

[–] baines@lemmy.cafe 28 points 1 month ago (2 children)

you go the other direction below the equator

[–] Bakkoda@lemmy.world 15 points 1 month ago

Legit gave me pause for like half a second. Damnit lol

[–] TonyTonyChopper@mander.xyz 5 points 1 month ago (1 children)

Isn't the southern hemisphere above the equator if you live there

[–] baines@lemmy.cafe 4 points 1 month ago

depends if you are normal or planar in ENU coordinates

[–] Hawanja@lemmy.world 25 points 1 month ago (1 children)

What's hard about it is people are fucking stupid.

[–] AquaTofana@lemmy.world 9 points 1 month ago (6 children)

I fucking suck at math and totally just re-proved it to myself with this problem lmao.

It didn't make sense to me to multiply the 3 & the 5 with zero consideration for the "2". I have ALWAYS struggled with the steps to solve these types of equations.

So the answer I got was 21. Some of us are just bad with numbers, I s'pose.

[–] borari@lemmy.dbzer0.com 13 points 1 month ago

The numbers in the equation and their totals are completely irrelevant to the order you perform the operations.

I don’t think it’s an issue of “being bad with numbers”, I think the issue is not understanding the logic or being able to understand the bottom up type of thinking or something.

[–] mfed1122@discuss.tchncs.de 6 points 1 month ago

This is absolutely not a problem of being bad with numbers. That's like if I had trouble reading a Chinese sentence about gardening and said I'm just bad with plants. My issue is that I'm not familiar with the notation used to explain the concept - not a problem with the concept itself that the notation merely arbitrarily symbolizes.

Being good or bad at math is not really an inherent thing, aside from some geniuses and some people with disabilities. If you want to be good at math, you can be!

[–] BCsven@lemmy.ca 2 points 1 month ago

Its order of operations, to get rid of brackets do the internal, then the 5 tells you there was 5 sets of the amount in brackets. Rather than 2+5 first.

[–] Rcklsabndn@sh.itjust.works 2 points 1 month ago

That's the answer I arrived at as well, don't feel so bad. I'm more of a writer than a calculator, though.

[–] Triasha@lemmy.world 2 points 1 month ago

If you don't remember pemdas, you can use the longer P.lease E.xcuse M.y D.ear A.unt S.ally.

[–] SmartmanApps@programming.dev 0 points 2 weeks ago

It didn’t make sense to me to multiply the 3 & the 5 with zero consideration for the “2”

That's what the order of operations rules say to do. 2 doesn't come into it until you get down to the Addition step.

[–] Chakravanti@monero.town 9 points 1 month ago (1 children)
[–] SlartyBartFast@sh.itjust.works 1 points 1 month ago

Cruel Parent's Thesis?

[–] SmartmanApps@programming.dev -2 points 2 weeks ago (1 children)

Pemdas, parenthesis first, for a total of 3

Nope, a total of 15.

Then multiplication

There isn't any Multiplication, only Addition and Brackets (and Subtraction inside Brackets).

[–] Triasha@lemmy.world 1 points 2 weeks ago (1 children)

And what do you do with the number inside the when you want to get rid of it?

[–] SmartmanApps@programming.dev 0 points 2 weeks ago (1 children)

And what do you do with the number inside the when you want to get rid of it?

You literally must distribute the coefficient before you can do anything with what is inside to remove Brackets, as per The Distributive Law, a(b+c)=(ab+ac), now you can work on getting rid of what is inside.

[–] Triasha@lemmy.world 1 points 2 weeks ago (1 children)

And what do you do with and and the b and then the a and the c? If you want to simplify the equation?

[–] SmartmanApps@programming.dev -2 points 2 weeks ago (1 children)

And what do you do with and and the b and then the a and the c? If you want to simplify the equation?

Add them, obviously 🙄

[–] Triasha@lemmy.world 1 points 1 week ago (1 children)
[–] SmartmanApps@programming.dev 1 points 1 week ago

And what do you do with and and the b and then the a and the c?

BTW, there's no "the a and the b" and "the a and the c", there's ab and ac, which need to be added. If a=2, b=3, and c=4, we have 2(3+4)=(6+8)=14