traaaaaaannnnnnnnnns
Welcome to /c/traaaaaaannnnnnnnnns, an anti-capitalist meme community for transgender and gender diverse people.
-
Please follow the Hexbear Code of Conduct
-
Selfies are not permitted for the personal safety of users.
-
No personal identifying information may be posted or commented.
-
Stay on topic (trans/gender stuff).
-
Bring a trans friend!
-
Any image post that gets 200 upvotes with "banner" or "rule 6" in the title becomes the new banner.
-
Posts about dysphoria/trauma/transphobia should be NSFW tagged for community health purposes.
-
When made outside of NSFW tagged posts, comments about dysphoria/traumatic/transphobic material should be spoiler tagged.
-
Arguing in favor of transmedicalism is unacceptable. This is an inclusive and intersectional community.
-
While this is mostly a meme community, we allow most trans related posts as we grow the trans community on the fediverse.
If you need your neopronouns added to the list, please contact the site admins.
Remember to report rulebreaking posts, don't assume someone else has already done it!
Matrix Group Chat:
Suggested Matrix Client: Cinny
https://rentry.co/tracha (Includes rules and invite link)
WEBRINGS:
🏳️⚧️ Transmasculine Pride Ring 🏳️⚧️
view the rest of the comments
To get the number of relationships youre interested in, its 2^n - n - 1 (which is also the sum of the number of binomial coefficients for a given n, and not for no reason). You could also set it up as a graph, then you have a complete graph (K n) and count subsets of at least size 2
Isn't the sum of binomial coefficients of n equal to 2^n? And then you remove (n choose 1) and (n choose 0) to get 2^n - n -1
Yeah, what the fuck was I thinking of??