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For someone to get electrocuted, the current needs to flow through their body. Electricity always follows the path of least resistance, so there's basically no way to do that from upstairs.
If you attach both terminals of the battery (or a stripped extension wire) that wouldn't do it. Assuming the pole is conductive, the electricity would just go into the screws, into the pole, across to the other screw and out. If the pole isn't conductive it would probably do nothing at all. Maybe the floor is conductive, in which case it would go into the screw, through the floor/ceiling and out the other screw. There's just no way to do it where the electricity flows from a screw, down the pole, into the body of the pole dancer, then somehow back out and up to the battery.
Even if the person who owned the stripper pole wanted to electrocute themselves it would be difficult. Assuming the pole is conductive, if you attached one electrode near the ceiling and one near the floor, the electricity would just flow through the pole. It wouldn't make a detour to go through the body of the pole dancer. You'd basically have to clip one side of the battery to your toe, the other side to the stripper pole, and then grab the pole with your hands. And, even then, it might not do it -- you'd have to have sweaty hands and toes to make the path through your body conductive.
I really hate the movie trope where people can get electrocuted by stepping into a puddle that has something electricity-related in it. It's almost as bad as the trope that you get blasted backwards if you're hit by a bullet / shotgun blast.
Incorrect.
stripper poles are tubes and spin on bearings. follow these instructions and you can most certainly electrocute someone with one.
You've put a worrying amount of thought into this.
🤣 I really didn't. I used to be a contractor and just understand how this stuff works.
best way to not kill yourself is to know the thousands of ways to die.
Do you really? It seems like you don't actually understand, because this won't work.
why not give it a try and come back to tell me I'm wrong.
I don't need to, because I know how electrical circuits work. I don't think you do. But, go on, explain why I'm wrong.
I didn't know I was talking to a professional here!
what would be the resistance of a plate of 16 gauge aluminum over 9 feet long?
I'll answer that for you, but first tell me what the (typical, average, ballpark) resistance of a human body is.
totally depends on conditions.
for a typical dry adult hand with a moderate to heavy amount of calloused skin, it's around 100k Ω. add any type of moisture or water like sweat it will be far less.
btw did you know the skin is the primary conduit of electrical conductively? only HV is a real danger to your organs because it permeates through all tissue.
side note. the internal resistance of the human body sits around 200-400 Ω.
so, what's the resistance of a 16 gauge plate of aluminum that's 9 feet long? in all honesty it's probably more likely to be 22 gauge though. which one would have the lower resistance?
So, a fair estimate for a human body's resistance is about 1000 Ω. That's a case when the hands are sweaty, or there's an open wound, or other cases where the skin isn't acting as a massive resistor and blocking any current from flowing.
According to this chart, a 16 gauge sheet of metal is about 1.5 mm thick. A 22 gauge is about 0.76 mm thick. I'm going to go in metric since everything is so much more straightforward.
So, 9 feet long is about 3m long. Apparently stripper poles typically come in 38, 45 and 50mm diameters, so, let's go for the smallest one to have the highest possible resistance. So, 38mm diameter means a circumference of 0.038 * Pi = 0.12m. So, the area of the pole is its circumference multiplied by its thickness, or about 0.12 * 0.00076 = approx 0.00009 m^2 (9*10^-5 m^2).
To calculate the resistance of something you need its resistivity. This table gives resistivities for common materials. Aluminum is listed at 2.82×10−8 Ωm. To calculate the resistance given the resistivity, cross-sectional area and length you plug the values into:
R = ρL / A
R = 3E-8Ωm * 3m / 0.00009m^2 = 3E-8 * 3 / 9E-5 = 0.333 E-3 = 3E-4Ω
Or, about 0.3 milliohms, or 300 microohms.
As a check, you can compare it to the resistance of a wire. Another chart gives the resistance of wires of various gauges at 1000 ft, or approx 300m. So, a 3m length of wire is going to be roughly 1/100th of that resistance. The values in the chart are on the order of 1 ohm at 300m, so 0.01 ohms (10 milliohms) at 3m. Of course, wires are much thinner than a whole pole, but wires are also designed to be good conductors, but 0.3 milliohms vs. 10 milliohms seems like we're in the right ballpark. So, even if the neighbour was dangling from a length of AWG 14 wire, and it was somehow not breaking, even then she'd be in no danger of electrocution.
This is all just back of the envelope estimation, but we're talking 6 orders of magnitude difference in resistance. No matter what the pole is made of, or how thin it is, it's still metal, and metal has much lower resistance than flesh. The current is going to stay in the pole, and the pole dancer is in no danger.
What makes you think that will work? That sounds like a very complicated way of just connecting the common to live with no human in the loop.
Ikr, this at least makes the pole get hot because current is actually running through part of it.
But at no point is a human part of the path of least resistance for the electricity.
the pole wouldn't get hot unless it was made of a ferrous metal like steel or iron. most of these poles should be made of aluminum.
You're confusing induction heating with resistant heating.
the gauge of metal the pole is made from is pretty thin. on top of that, it's very likely to be made from aluminum.
if electricity follows the path of least resistance, it would be through the person.
Ok, you're still failing here. The water content of a human body is irrelevant. A large contact area is irrelevant.
Let me make it easier for you. As I'm sure you know, to be electrocuted an electrical current needs to flow through someone's body. What part of the neighbour's body is the current going to enter, and which part is it going to leave?