this post was submitted on 21 Jul 2025
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submitted 5 days ago* (last edited 5 days ago) by SSUPII@sopuli.xyz to c/lemmyshitpost@lemmy.world
 
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[–] SpruceBringsteen@lemmy.world 80 points 5 days ago (20 children)

Alright science nerds how cold does the freezer actually have to be to get a jagerpop that is consistent?

[–] Karyoplasma@discuss.tchncs.de 60 points 5 days ago* (last edited 5 days ago) (14 children)

tl;dr Around -21°C (-9°F). Realistically probably a tad lower than that.

Formula for freezing point depression is:

ΔT~f~ = i * K~f~ * m

ΔT~f~ = freezing point depression in absolute degrees (C or K)

i = van 't Hoff factor, the number of particles the solutes splits into, ethanol does not split, so 1

K~f~ = freezing point suppression constant, for water 1.86°C * kg / mol

m = molality of the solution (aka how much you add), looked it up and it's 11.42 mol for 40% ethanol/water mixture

1 * 1.86 * 11.42 = 21.2412°C

In reality, Jägermeister is not a pure water/ethanol mixture and all that other stuff in there drops the freezing point by a bit as well. Ethanol is the biggest contributor tho. So maybe add 1° or 2° to this.


Is Jägermeister really that green in the US?

[–] Hacksaw@lemmy.ca 6 points 4 days ago (3 children)

I did not know about that formula, very cool. It seems linear (unless the molality is a non-linear term), whereas the empirical data gets pretty whacky at higher concentrations. Maybe its validity is for low concentrations? I'm getting closer to -27C from this plot

Plot of freezing point of water vs alcohol concentration

Source www.researchgate.net/figure/Melting-freezing-points-of-alcohol-aqueous-solutions-vs-solvent-concentration-Weast_fig6_273304489

Either way that's getting close to "don't lick it" temperatures lol!

[–] Karyoplasma@discuss.tchncs.de 4 points 4 days ago* (last edited 4 days ago) (2 children)

The figure you've linked plots concentration by weight (wt.%), while the alcohol content of drinks is usually given in volume percent (v/v). Ethanol is less dense than water, so a 30% concentration by weight is a higher concentration by volume.

Imagine a 100g solution of 30wt.% alcohol. That means that 30g are ethanol and 70g are water. the 70g of water translate to 70ml volume (density 1g/ml) and the 30g of ethanol translate to 30/0.789 = 38.02ml. So in total, you would have 108.02ml of liquid and the concentration of ethanol by volume would be 38.02/108.02 = 35.2%.

Why it gets wacky at the end: Ethanol freezes at -114°C, water freezes at 0°C, but at specific concentrations, the eutectic composition, the solution freezes at a lower point than either of its constituents. The eutectic point is the lowest possible freezing point of a solution. The formula I gave is not applicable to eutectic solutions and is an approximation based on perfect solutions (which in reality don't really exist).

[–] Ashiette@lemmy.world 2 points 4 days ago* (last edited 4 days ago)

There is only one error in your equations (and that doesn't change much about your point) is that the volume of that mixture is slightly lower than 108mL and should sit at about 107.1mL.

Volume reduction in water - ethanol mixtures

[–] Hacksaw@lemmy.ca 0 points 4 days ago

Amazing, thanks for the clarification!

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