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[-] blanketswithsmallpox@kbin.social 32 points 1 year ago* (last edited 1 year ago)

I'm a little sad nobody has done the correct math and it's been too long for me to do it off the top of my head lol.

A^2+B^2=C^2? What distance are the diagonals if the sides are 6' apart?

6x6 + 6x6 = sqrt72 = 8.49' !

I did it bois. Ty calculator for sqrt72...

[-] Kongpiler@lemm.ee 25 points 1 year ago

Now do the conversion factor from feef to feet!

[-] TheFriendlyDickhead@lemm.ee 21 points 1 year ago

The diagonal is 6ft. The side is 6 ft. So 6² + 6feef² = 6²

1 feef = 0ft

[-] exu@feditown.com 5 points 1 year ago

Now, what's the length of the sides if the diagonals are 6ft?

[-] TheFriendlyDickhead@lemm.ee 5 points 1 year ago* (last edited 1 year ago)

Thats easy.
6 * 6 = 36
36 = a² + b²
Lets assume a = b
So a² = 18 = b²
a = b = 4,2426406871

[-] shootwhatsmyname@lemm.ee 1 points 1 year ago

What if every initial value is unknown?

[-] MrMamiya@feddit.de 2 points 1 year ago
[-] Unanimous_anonymous@lemmy.ml 2 points 1 year ago

8.49'!~=116699.97'

I am a human, hear me rar.

this post was submitted on 13 Aug 2023
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