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Mind=Blown (lemmy.fmhy.ml)
submitted 1 year ago by upsiderue@lemmy.fmhy.ml to c/memes@lemmy.ml
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[-] newIdentity@sh.itjust.works 105 points 1 year ago

Actually 0.99... is the same as 1. They both represent the same number

https://en.m.wikipedia.org/wiki/0.999...

[-] Kalkaline@lemmy.one 36 points 1 year ago

It's so dumb and it makes perfect sense at the same time. There is an infinitely small difference between the two numbers so it's the same number.

[-] KoboldCoterie@pawb.social 55 points 1 year ago* (last edited 1 year ago)

There is no difference, not even an infinitesimally small one. 1 and 0.999... represent the exact same number.

[-] clutchmatic@lemmy.world 7 points 1 year ago

They only look different because 1/3 out of 1 can't be represented well in a decimal counting system.

[-] funnystuff97@lemmy.world 5 points 1 year ago* (last edited 1 year ago)

Right, it's only a problem because we chose base ten (a rather inconvenient number). If we did math in base twelve, 1/3 in base twelve would simply be 0.4. It doesn't repeat. Simply, then, 1/3 = 0.4, then (0.4 × 3) = (0.4 + 0.4 + 0.4) = 1 in base twelve. No issues, no limits, just clean simple addition. No more simple than how 0.5 + 0.5 = 1 in base ten.

One problem in base twelve is that 1/5 does repeat, being about 0.2497.... repeating. But eh, who needs 5? So what, we have 5 fingers, big whoop, it's not that great of a number. 6 on the other hand, what an amazing number. I wish we had 6 fingers, that'd be great, and we would have evolved to use base twelve, a much better base!

[-] clutchmatic@lemmy.world 1 points 1 year ago

I mean, there is no perfect base. But the 1/3=0.333... thing is to be understood as a representation of that 1 split three ways

[-] fahfahfahfah@lemmy.billiam.net 4 points 1 year ago* (last edited 1 year ago)

Well, technically “infinitesimally small” means zero sooooooooo

Edit: this is wrong

[-] KoboldCoterie@pawb.social 13 points 1 year ago

An infinitesimal is a non-zero number that is closer to zero than any real number. An infinitesimal is what would have to be between 0.999... and 1.

[-] fahfahfahfah@lemmy.billiam.net 8 points 1 year ago

You are correct and I am wrong, I always assumed it to mean the same thing as a limit going to infinity that goes to 0

[-] KoboldCoterie@pawb.social 8 points 1 year ago* (last edited 1 year ago)

It's a weird concept and it's possible that I'm using it incorrectly, too - but the context at least is correct. :)

Edit: I think I am using it incorrectly, actually, as in reality the difference is infinitesimally small. But the general idea I was trying to get across is that there is no real number between 0.999... and 1. :)

[-] LegendofZelda64@lemmy.fmhy.ml 2 points 1 year ago

I think you did use it right tho. It is a infinitesimal difference between 0.999 and 1.

"Infinitesimal" means immeasurably or incalculably small, or taking on values arbitrarily close to but greater than zero.

[-] kogasa@programming.dev 5 points 1 year ago

The difference between 0.999... and 1 is 0.

It is possible to define a number system in which there are numbers infinitesimally less than 1, i.e. they are greater than every real number less than 1 (but are not equal to 1). But this has nothing to do with the standard definition of the expression "0.999...," which is defined as the limit of the sequence (0, 0.9, 0.99, 0.999, ...) and hence exactly equal to 1.

[-] Ghoelian@feddit.nl 2 points 1 year ago

Wait what

I always thought infinitesimal was one of those fake words, like gazillion or something

[-] KoboldCoterie@pawb.social 3 points 1 year ago

It sounds like it should be, but it's actually a real (or, non-real, I suppose, in mathematical terms) thing! :)

[-] iAmTheTot@kbin.social 26 points 1 year ago

No, it's not "so close so as to basically be the same number". It is the same number.

[-] nachom97@lemmy.world 5 points 1 year ago

They said its the same number though, not basically the same. The idea that as you keep adding 9s to 0.9 you reduce the difference, an infinite amount of 9s yields an infinitely small difference (i.e. no difference) seems sound to me. I think they’re spot on.

[-] iAmTheTot@kbin.social 6 points 1 year ago

No, there is no difference. Infitesimal or otherwise. They are the same number, able to be shown mathematically in a number of ways.

[-] nachom97@lemmy.world 5 points 1 year ago

Yes, thats what we're saying. No one said it's an infinitesimally small difference as in hyperbolically its there but really small. Like literally, if you start with 0.9 = 1-0.1, 0.99 = 1-0.01, 0.9... n nines ...9 = 1-0.1^n. You'll start to approach one, and the difference with one would be 0.1^n correct? So if you make that difference infinitely small (infinite: to an infinite extent or amount): lim n -> inf of 0.1^n = 0. And therefore 0.999... = lim n -> inf of 1-0.1^n = 1-0 = 1.

I think it's a good way to rationalize, why 0.999... is THE SAME as 1. The more 9s you add, the smaller the difference, at infinite nines, you'll have an infinitely small difference which is the same as no difference at all. It's the literal proof, idk how to make it more clear. I think you're confusing infinitely and infinitesimally which are not at all the same.

[-] mrcarrot@lemmy.calebmharper.com 2 points 1 year ago

Technically you're both right as there are no infinitesimals in the real number system, which is also one of the easiest ways to explain why this is true.

[-] dandroid@dandroid.app -1 points 1 year ago

That's what it means, though. For the function y=x, the limit as x approaches 1, y = 1. This is exactly what the comment of 0.99999... = 1 means. The difference is infinitely small. Infinitely small is zero. The difference is zero.

[-] newIdentity@sh.itjust.works 0 points 1 year ago

Infinity small is infinity small. Not zero

[-] dandroid@dandroid.app 1 points 1 year ago

That's simply not true, as I demonstrated in my example.

[-] Nioxic@lemmy.world 7 points 1 year ago

There was also a veritasium video about this.

It was interesting.

[-] Minzert@lemmy.fmhy.ml 1 points 1 year ago

His videos always are

[-] upsiderue@lemmy.fmhy.ml 0 points 1 year ago

If .99....9=1, then 0.999...8=0.999...9, 0.99...7=0.999...8, and so forth to where 0=1?

[-] Tchallenge@social.fossware.space 51 points 1 year ago* (last edited 1 year ago)

The tricky part is that there is no 0.999...9 because there is no last digit 9. It just keeps going forever.

If you are interested in the proof of why 0.999999999... = 1:

0.9999999... / 10 = 0.09999999... You can divide the number by 10 by adding a 0 to the first decimal place.

0.9999999... - 0.09999999... = 0.9 because the digit 9 in the second, third, fourth, ... decimal places cancel each other out.

Let's pretend there is a finite way to write 0.9999999..., but we do not know what it is yet. Let's call it x. According to the above calculations x - x/10 = 0.9 must be true. That means 0.9x = 0.9. dividing both sides by 0.9, the answer is x = 1.

The reason you can't abuse this to prove 0=1 as you suggested, is because this proof relies on an infinite number of 9 digits cancelling each other out. The number you mentioned is 0.9999...8. That could be a number with lots of lots of decimal places, but there has to be a last digit 8 eventually, so by definition it is not an infinite amount of 9 digits before. A number with infinite digits and then another digit in the end can not exist, because infinity does not end.

[-] upsiderue@lemmy.fmhy.ml 9 points 1 year ago

Wonderful explanation. It got the point across.

[-] ripjackie@lemmy.dbzer0.com 5 points 1 year ago

That is the best way to describe this problem I've ever heard, this is beautiful

[-] wumpoooo@lemmy.world 2 points 1 year ago

Maybe a stupid question, but can you even divide a number with infinite decimals?

I know you can find ratios of other infinitely repeating numbers by dividing them by 9,99,999, etc., divide those, and then write it as a decimal.

For example 0.17171717.../3

(17/99)/3 = 17/(99*3) = 17/297

but with 9 that would just be... one? 9/9=1

That in itself sounds like a basis for a proof but idk

[-] quicksand@lemmy.world 2 points 1 year ago

Yes that's essentially the proof I learned in high school. 9/9=1. I believe there's multiple ways to go about it.

[-] DrMango@lemmy.world 2 points 1 year ago

This is the kind of stuff I love to read about. Very cool

[-] DesolateMood@lemm.ee 9 points 1 year ago

0.999...8 does not equal 0.999...9 so no

[-] TeddE@lemmy.world 2 points 1 year ago

If the "…" means 'repeats without end' here, then saying "there's an 8 after" or "the final 9" is a contradiction as there is no such end to get to.

There are cases where "…" is a finite sequence, such as "1, 2, … 99, 100". But this is not one of them.

[-] DesolateMood@lemm.ee 3 points 1 year ago

I'm aware, I was trying to use the same notation that he was so it might be easier for him to understand

[-] somePotato@sh.itjust.works 6 points 1 year ago

Your way of thinking makes sense but you're interpreting it wrong.

If you can round up and say "0,9_ = 1" , then why can't you round down and repeat until "0 = 1"? The thing is, there's no rounding up, the 0,0...1 that you're adding is infinitely small (inexistent).

It looks a lot less unintuitive if you use fractions:

1/3 = 0.3_

0.3_ * 3 = 0.9_

0.9_ = 3/3 = 1

[-] icosahedron@ttrpg.network 4 points 1 year ago

No, because that would imply that infinity has an end. 0.999… = 1 because there are an infinite number of 9s. There isn’t a last 9, and therefore the decimal is equal to 1. Because there are an infinite number of 9s, you can’t put an 8 or 7 at the end, because there is literally no end. The principle of 0.999… = 1 cannot extend to the point point where 0 = 1 because that’s not infinity works.

[-] kadu@lemmy.world 4 points 1 year ago

Huh... Where did you get "0.999... = 0.999...8" from? There's a huge difference here.

[-] upsiderue@lemmy.fmhy.ml -4 points 1 year ago* (last edited 1 year ago)

Read carefully. I wrote a finite number(0.999...9)

[-] Cortell@lemmy.world 5 points 1 year ago

Think carefully

What does 0.99…8 represent to you exactly

If it’s an infinite amount of 9s then it can’t end in an 8 because there’s an infinite amount of 9s by definition so it’s not a real number

[-] dlove67@feddit.nl 3 points 1 year ago

There is no .99...8.

The ... implies continuing to infinity, but even if it didn't, the "8" would be the end, so not an infinitely repeating decimal.

[-] XpeeN@sopuli.xyz 2 points 1 year ago* (last edited 1 year ago)

If you really wants to understand the concept , you need to learn about limits

this post was submitted on 17 Jul 2023
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