this post was submitted on 25 May 2026
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[–] toofpic@lemmy.world 32 points 1 month ago (5 children)

The number of attempts is not mathematically affecting the outcome of a single attempts - statistics don't "owe you" any specific outcomes, just based on previous outcomes. It will be the same formula for each

[–] ergonomic_importer@piefed.ca 8 points 1 month ago (1 children)

Statistics also won't help you with the guilt when the tram runs over 5 people and now it's just you and the one guy you saved now trauma bonded.

[–] abbadon420@sh.itjust.works 6 points 1 month ago (2 children)

I'm not the idiot who tues people to train tracks. I won't be feeling much guilt

[–] prime_number_314159@lemmy.world 3 points 1 month ago

What if, by taking some seemingly benign action, followed by a series of unforeseeable events, you have caused the people to be on the train tracks?

[–] dream_weasel@sh.itjust.works 1 points 1 month ago

Hey I'm not an idiot.

[–] Enekk@lemmy.world 6 points 1 month ago (1 children)

Actually, in this case, unless they are... refilling... the hostages each run, the results of previous runs do affect each additional run. Unless you feel that running someone over the second time kills them a second time.

[–] dream_weasel@sh.itjust.works 4 points 1 month ago

"aww damn, 5 people are double dead"

[–] someone@lemmy.today 1 points 1 month ago* (last edited 1 month ago)

I am not sure this is technically true if the probabilities have any dependence.

[–] DarrinBrunner@lemmy.world 0 points 1 month ago (1 children)

I didn't need math to know that the only way I see a guy beheaded is if I don't pull the lever, so we got to the same answer.

[–] toofpic@lemmy.world 1 points 1 month ago

If you don't, you will, look at the post again