[-] zenharbinger@lemmy.world 8 points 3 days ago

Not free, but I love sublime text.

[-] zenharbinger@lemmy.world 21 points 1 month ago* (last edited 1 month ago)

They can use up to 2 years (I think) of a previous term. LBJ could have had 2 full terms plus the remainder he had from JFK.

[-] zenharbinger@lemmy.world 27 points 2 months ago

That happens when you are a good developer too.

[-] zenharbinger@lemmy.world 32 points 6 months ago

He has no cash, it's all tied up in real estate. He would have to sell to get the bond money.

Probably could get a 'donor' to purchase though.

[-] zenharbinger@lemmy.world 100 points 6 months ago

The article says she let another person use her card for a fee.

[-] zenharbinger@lemmy.world 34 points 7 months ago

some partitions are useful. Keeping /var and /tmp separate can stop DoS attacks by now allowing logs to fill the entire drive /home means you can wipe the / partition and keep user data.

[-] zenharbinger@lemmy.world 24 points 8 months ago

Shocked Picachu

0

I used to work in the field of machine translation and would like to know more about how they are doing this translation. 10 years ago, we saw the explosion of statistical and training based translations. However, these are better suited for the cloud, so does anyone know where I can find info on how Firefox does their translations?

[-] zenharbinger@lemmy.world 32 points 1 year ago

This is the first thing I thought of as well. It's never been "just use what you want". It got better for a while as JavaScript and CSS normalized. Now it's trash again.

[-] zenharbinger@lemmy.world 19 points 1 year ago

buffer overflow in reality

[-] zenharbinger@lemmy.world 17 points 1 year ago

22 obviously

[-] zenharbinger@lemmy.world 18 points 1 year ago* (last edited 1 year ago)

I found the easiest way to think about it as if there are 10 doors, you choose 1, then 8 other doors are opened. Do you stay with your first choice, or the other remaining door? Or scale up to 100. Then you really see the advantage of swapping doors. You have a higher probability when choosing the last remaining door than of having correctly choosen the correct door the first time.

Edit: More generically, it's set theory, where the initial set of doors is 1 and (n-1). In the end you are shown n-2 doors out of the second set, but the probability of having selected the correct door initially is 1/n. You can think of it as switching your choice to all of the initial (n-1) doors for a probability of (n-1)/n.

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zenharbinger

joined 1 year ago