this post was submitted on 11 Feb 2025
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It can look dumb, but I always had this question as a kid, what physical principles would prevent this?

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[–] propter_hog@hexbear.net 50 points 3 days ago (4 children)

So I found a dowel rod online that's 1 meter long by 25 mm in diameter made of beech, which is pretty typical for this kind of rod. Each rod weighs 420 g. 300,000 km is 300,000,000 m. So for a dowel rod to be 300,000,000 m long, it would weigh 126,000,000,000 g, or 126,000,000 kg. You would never be able to push this rod. If you had a magical hydraulic ram that could, it would just compress the soil under it. This is on the scale of the foce released from an atomic bomb.

But let's throw that out and pretend the whole thing weighs 420 grams instead. Maybe it's made of a novel, space-age material instead of beech. And since you've said it can't bend or break, the portion at the surface of the earth would be spinning at roughly 1,000 kph (due to the rotation of the earth), and the portion at the end of the rod would be spinning at about 28 km/s. Most of the mass of the rod would be spinning faster than escape velocity, so you wouldn't be able to hold onto it. It would be gone almost instantly.

Let's pretend you could hold onto it. Then the person on the moon couldn't hold it, because the earth rotates on its axis about 28 times faster than the moon travels around its orbit. So you can see how this problem devolves into ever more layers of magic and hand-waiving.

The final problem is the fundamental difference between classroom physics and material engineering. If you could fix the moon to the end of the rod, and you used a space-age material that weighs 420 g for the whole thing, and it could be so rigid as to not bend, then it would have to break instead. If, instead, it's designed to not break, then it must be able to bend. This is just how real materials work. But even if it does neither, or at most only bends a little, it is still true that as you push on the rod it would compress. So the tip wouldn't move at first. The pressure would move through the rod like a wave. You can't send information faster than light.

[–] Ithorian@hexbear.net 13 points 3 days ago

rat-salute Excellent write up.

[–] TheGuyTM3@lemmy.ml 8 points 3 days ago* (last edited 3 days ago) (1 children)

Yes, about my setting, it was pretty much an excuse to illustrate the experiment, with like you said, a bit too much of magic.

The moon being on a straight distance of approximately 1 light second, i didn't had found another place to put this experiment on. So I didn't take into account the herculean strengh needed, the movement of the earth and the moon and the gravity.

Someone gave a link to an answer of my question, with a more realistic take on the position of the other end, but your explanations are still welcome for this moon setting and the "moon elevator" problem :)

(i know i may have broken english sometimes, sorry about that)

[–] propter_hog@hexbear.net 7 points 3 days ago

(i know i may have broken english sometimes, sorry about that)

Not at all! I couldn't tell you aren't a native speaker. Regarding a "moon elevator", or more realistically a space elevator, these kinds of Herculean physics problems are exactly what people are trying to iron out. The forces involved are astronomical.

[–] CrabAndBroom@lemmy.ml 5 points 3 days ago (1 children)

Yeah IIRC that even applies to things like gravity as well. As in, we aren't actually orbiting around where is sun is, we're orbiting around where it was ~8 minutes ago because the sun is about 8 light-minutes from Earth.

[–] Cutecity@hexbear.net -3 points 3 days ago (2 children)

No, gravity is faster than light. If there was this lag, we wouldn't have stable orbits exactly because of the lag you describe. Wave functions of photons also collapse faster than light when they hit absorbent material.

[–] vrighter@discuss.tchncs.de 5 points 3 days ago (1 children)

wave function (something that does not travel) collapses (something that does not move either) faster than light (themselves?)

this word soup does not make sense

[–] Cutecity@hexbear.net 1 points 3 days ago

I used wave function as a bad form of shorthand for the general properties of the photon, such as the theoretically infinitely extending magnetic and electric fields. Those associated fields stop existing when the photon is absorbed onto a screen. They collapse faster than light can travel. This doesn't ruin much of modern theories, because there doesn't seem to be a way to transfer usable information through this phenomenon.

[–] hedgehog@ttrpg.network 4 points 3 days ago (1 children)
[–] Cutecity@hexbear.net 1 points 3 days ago (1 children)

I don't think gravitational waves traveling at the speed of light is the same as the gravitational attraction being apparently felt faster than light travels. Similarly, electric attraction between + and - charges is different from electromagnetic waves being transmitted in the field. It's not light that is "communicating" that attraction.

[–] hedgehog@ttrpg.network 1 points 3 days ago (1 children)

I don't think gravitational waves traveling at the speed of light is the same as the gravitational attraction being apparently felt faster than light travels.

I don’t know how you would measure gravitational waves without measuring gravitational attraction.

It's not light that is "communicating" that attraction.

Nobody said it was. The “speed of light” isn’t about “light”. Gravity propagates at the same speed, aka “c.”

This Reddit discussion on r/AskPhysics might help clear up your misconceptions. Notably:

Just to clarify: when people talk about the speed of gravity, they mean the speed at which changes propagate. It's the answer to questions like: if I take the Sun and wiggle it around, how long does it take for the Earth to feel the varitation in the force of gravity? And the answer is that changes in gravity travel at the speed of light.

But that's not what you're asking about. Whenever you're close to the Earth, gravity is always acting on you: it's not waiting until you step off a cliff, like in the Coyote and the Roadrunner. The very instant your foot is no longer on the ground, gravity will start to move it downwards. The only detail is that it takes some time for it to build up an appreciable speed, and this is what allows us to do stuff like jump over pits: if you're fast enough, gravity won't be able to accelerate you enough - but gravity is still there.

I get the sense that you’re thinking about the second scenario when objecting to the concept that gravity travels at the speed of light.

[–] Cutecity@hexbear.net 1 points 2 days ago

I was definitely talking about the first scenario, as is mostly everyone else. I know not everyone admits gravity (gravitational attraction) might travel faster than light as in the "sun moving" thought experiment. I'm not confused, I'm discussing like everybody else. You linked an article about gravitational waves which must transmit through some sort of gravitational field and they might transmit at approximately c as predicted in general relativity. What I believe is that gravitational attraction, so the general effect of the field will be felt as if it acts almost instantly, and that does not contradict anything about the waves in that field. Because the waves in that field are not responsible for the attraction. This is similar to how photons do not mediate the magnetic attraction in magnets even though they are electromagnetic waves. The current theories (which you are pulling from) manage to mathematically explain that in our moving sun thought experiment, the gravitational force coming from the sun appears to "update" instantly as if it's acting from it's actual position without the lag, because of (to my understanding) the curvature of space-time. So I personally can't fight that on mathematical grounds because that's above my understanding. But in the end it doesn't change much of anything to our discussion, because the force of gravity still updates "as if" it was mostly instantaneous and that's the standard model. Meanwhile, gravitational waves do travel at c but are kind of unrelated to the continous force. They are merely fluctuations in that force. Please keep poking and challenging me at that, I'm still wrapping my head around it and will need better and better sources while I'm hyper focusing on it until I move on lol

[–] makingStuffForFun@lemmy.ml 4 points 3 days ago

That was excellent. Thank you