this post was submitted on 22 Jun 2024

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Not everything can be done in constant time, that's O(k) (sh.itjust.works)

submitted 4 months ago by alphacyberranger@sh.itjust.works to c/programmer_humor@programming.dev

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[–] catastrophicblues@lemmy.ca 2 points 4 months ago (1 children)

Surely you could implement this via a sorting algorithm? If you can prove the distance function is a metric and both lists contains elements from the same space under that metric, isn’t the answer to sort both?

[–] jjagaimo@lemmy.ca 7 points 4 months ago

It's essentially the traveling salesman problem