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Statically Typed Functional Programming with Python 3.12 (wickstrom.tech)
submitted 5 months ago by mao@lemmy.sdf.org to c/python@programming.dev
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Neato

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[-] nxdefiant@startrek.website 1 points 5 months ago

x = foo(y:=bar(), baz(), y) or z should work assuming foo bar and baz are functions being called?

if this is setting y to the effect of bar() + running baz after, then:

x = [bar(), baz()][0] or z

might work

and if you need y to be defined for later use:

x = [(y:=bar()), baz()][0] or z

but thats from memory, not sure if that will even run as written.

if I get to a real computer I'll try that with an actual if statement instead of a bastardized ternary.
[-] FizzyOrange@programming.dev 2 points 5 months ago

foo isn't a function, it's a bool. But in any case, as you can see the answer is "with terrible hacks". Python is not a functional language. It is imperative.

[-] nxdefiant@startrek.website 0 points 5 months ago

Yeah, never said it was, just that if you really want to emulate that style you mostly can.

this post was submitted on 24 May 2024
44 points (97.8% liked)

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