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Kansas^-1 (sh.itjust.works)
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[-] onion@feddit.de 5 points 5 months ago* (last edited 5 months ago)

Kansas to the minus one? One over Kansas?

[-] slacktoid@lemmy.ml 10 points 5 months ago
[-] Wilzax@lemmy.world 5 points 5 months ago* (last edited 5 months ago)

Kansas^-1 (x) not kansas (x)^-1

[-] mexicancartel@lemmy.dbzer0.com 2 points 3 months ago
[-] Wilzax@lemmy.world 1 points 3 months ago

Yeah it's a play how arcsin(x) = sin^-1(x), arccos = cos^-1(x), and arctan = tan^-1(x)

[-] onion@feddit.de 1 points 5 months ago

So one over Kansas times x not Kansas times one over x?

[-] Wilzax@lemmy.world 3 points 5 months ago* (last edited 5 months ago)

Kansas is a function name, not a variable in this notation. Otherwise it would be (Kansa/s)(x) which simplifies to (a^2) (k)(n)(x)

this post was submitted on 01 May 2024
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