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submitted 1 year ago by poVoq@slrpnk.net to c/space@beehaw.org
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[-] zhunk@beehaw.org 1 points 1 year ago* (last edited 1 year ago)

For a geostationary orbit, which is where the center of mass of a space elevator would be:

h = ³√ G * m * T² / ( 4 * π² ) - r

  • h: orbit height (m)
  • G: gravitational constant
  • m: mass of celestial body (kg)
  • T: period of rotation (s)
  • r: radius of celestial body (m)

So, if the mass goes way up, the height of the orbit will, too, unless something crazy happens like the planet spinning super fast.

this post was submitted on 11 Jul 2023
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