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Well sorry how I phrased that. But explain to me how that works.
I already did some math. Ok the golf is going what? 130? Then the TT goes 195kmph.
The VW EA888 is not available as 130hp edition, especially not in a Golf, there it's used in the R Models or as 190hp edition. The smallest equivalent engine I could find was the Golf VI 1.8T with 160hp. The CDAA engine.
But ok, let's just ignore the engines for now, focus on resistance.
In this calculation I use a density of 1.29kg/m³.
Audi TT8J with the spoiler retracted has a drag coefficient of 0.31 and that's really impressive. We have a surface area of 2.09m² and a speed of 195kmph.
That results in 1226.12N drag force applied to the Audi TT
The Golf has CW values ranging from Golf 1 with 0.42 to 0.27 Golf 7 Blue motion.
But let's assume we have a Golf 6 from 2010 with 0.31 CW (sounds familiar) a surface area of 2.23m² and the speed of 130kmph. That results in 581.44N drag force.
Explain to me like, how will the Audi manage to go that fast, with that drag force applied and consume the same amount of fuel like the Golf? I mean even the engine should be the same size. So either the Audi TT has a magical rolling resistance that he can compete with the golf fuel consumption. Don't know how the math here work's, especially in regard that the golf is 100kg lighter.
Are there much more efficient air conditioning systems/assistant systems in the sports car that reduce the fuel consumption?
I don't know... The Audi you mentioned consumes 7,7L/100km. Let's take the worst engine the Golf 6 has, that has less horsepower that the Audi: the VW EA 113 1.6L with 102 hp. Btw the same engine plattform like the Audi's engine. That consumes 7.1L/100km.
So please, enlighten me. How can the "sports car" go 50% faster and consume the same amount of fuel? The drag force is more than doubled. The engine consumes by default more. How?