this post was submitted on 05 Apr 2025
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std::endl provides zero portability benefits. C++ does have a portable newline abstraction, but it is called
\n, not endl.No, there's no guarantee that in every context \n is translated portably.
The same is true of std::endl. std::endl is simply defined as
<< '\n' << std::flush; nothing more, nothing less. In all cases where endl gives you a "properly translated" newline, so does\n.Yeah it's an artificial dichotomy based on a popular misconception of what std::endl is and how \n is interpreted.
Ultimately it does not ask about line endings, but about flushing, which is a completely orthogonal question.