this post was submitted on 20 Feb 2026
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[–] towerful@programming.dev 8 points 15 hours ago (1 children)

The person in the middle would be supporting twice the weight of the person over the hole, and they would have to do it twice.
The person over the hole and the person not over the hole just has to hang on.

When the middle person is over the hole, the people at each end support half the weight of the person over the hole.

The length of the pole doesn't matter, as long as the person in the middle is in the middle of the pole and that the pole is more than twice the length of the hole.
If the pole was significantly long enough, then the force on the middle person could be reduced significantly, but it will always be more than the weight of 1 person.

[–] Zamboni_Driver@lemmy.ca 1 points 13 hours ago

True, you can tell I'm not very good at math.

So when someone is dangling the person in the middle will experience the weight of both of the other people, and the person at the other end will experience the entire bodyweight of the person dangling as upwards force on the log that they will have to hold onto. So if the two people on the ends weigh the same, does the the person at the other end get lifted off the ground by the weight of the dangling person; assuming the middle person is strong enough to hold them both up?

I guess what happens practically is that the person in the middle collapses onto the ground and the log gets torn out of the hands of the person at the other end and the dangler goes into the pit?