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[-] JackbyDev@programming.dev 7 points 1 year ago* (last edited 1 year ago)

Using only tabs for indentation and only spaces for alignment will never result in crap alignment when adjusting tabstops because the alignment does not use tabs.

This is using both tabs and spaces for alignment.

--->func foo(int i,
--->--->     int j);

Observe what adjusting the tabs does,

->func foo(int i,
->->     int j);

This uses only spaces for alignment,

--->func foo(int i,
--->         int j);

When converted the alignment is maintained because the tabstops aren't used for alignment, only for indentation.

->func foo(int i,
->         int j);
this post was submitted on 05 Sep 2023
167 points (79.7% liked)

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