this post was submitted on 05 Dec 2024
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Advent Of Code

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An unofficial home for the advent of code community on programming.dev! Other challenges are also welcome!

Advent of Code is an annual Advent calendar of small programming puzzles for a variety of skill sets and skill levels that can be solved in any programming language you like.

Everybody Codes is another collection of programming puzzles with seasonal events.

EC 2025

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console.log('Hello World')

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Day 5: Print Queue

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[–] HeckGazer@programming.dev 1 points 1 year ago* (last edited 1 year ago)

Because you're just sorting integers and in a single pass, the a == b and a > b distinction doesn't actually matter here, so the cmp can very simply be is a|b in rules, no map needed.

Edit: I realise it would be a sidegrade for your case because of how you did P1, just thought it was an interesting insight, especially for those that did P1 by checking if the input was sorted using the same custom compare.

func solution(input string) (int, int) {
	// rules: ["a|b", ...]
	// updates: [[1, 2, 3, 4], ...]
	var rules, updates = parse(input)

	sortFunc := func(a int, b int) int {
		if slices.Contains(rules, strconv.Itoa(a)+"|"+strconv.Itoa(b)) {
			return -1
		}
		return 1
	}

	var sumOrdered = 0
	var sumUnordered = 0
	for _, update := range updates {
		if slices.IsSortedFunc(update, sortFunc) {
			sumOrdered += update[len(update)/2]
		} else {
			slices.SortStableFunc(update, sortFunc)
			sumUnordered += update[len(update)/2]
		}
	}
	return sumOrdered, sumUnordered
}