Day 3: Mull It Over

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[-] janAkali@lemmy.one 2 points 2 weeks ago

Nim

From a first glance it was obviously a regex problem.
I'm using tinyre here instead of stdlib re library just because I'm more familiar with it.

import pkg/tinyre

proc solve(input: string): AOCSolution[int, int] =
  var allow = true
  for match in input.match(reG"mul\(\d+,\d+\)|do\(\)|don't\(\)"):
    if match == "do()": allow = true
    elif match == "don't()": allow = false
    else:
      let m = match[4..^2].split(',')
      let mult = m[0].parseInt * m[1].parseInt
      result.part1 += mult
      if allow: result.part2 += mult

Codeberg repo

[-] sjmulder@lemmy.sdf.org 3 points 2 weeks ago

I shy away from regexes for these parsing problems because part 2 likes to mess those up but here it worked beautifully. Nice and compact solution!

this post was submitted on 03 Dec 2024

20 points (95.5% liked)

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