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Me_irl (lemm.ee)
submitted 4 weeks ago* (last edited 4 weeks ago) by sag@lemm.ee to c/avatar@lemmy.world
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[-] LeFantome@programming.dev 2 points 4 weeks ago
[-] Snazz@lemmy.world 2 points 4 weeks ago* (last edited 4 weeks ago)

Because there are no units, the equation can only be used to compare one rate of work to another rate of work at a different time (or a different deadline).

ratio of rate of work at time t1 compared to rate of work at time t2

= rate_of_work(t1, d) / rate_of_work(t2, d)

= (1 / (d - t1)) / (1 / (d - t2))

= (d - t2) / (d - t1)

This works because the only variables left are in the same units, even if that unit itself is unspecified.

[-] amon@lemmy.world 1 points 1 week ago

could a unit for this be s^-1^?

this post was submitted on 20 Nov 2024
290 points (98.7% liked)

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