this post was submitted on 11 Feb 2026
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No matter what wouldn't this grow to infinite passengers? Is that supposed to be the point?
Because any even number is going to halve itself down to ~~1, which is odd~~ an odd number, then double plus one will always make another odd number so it would grow to infinity.
Edit: Misread the problem, read replies for explanations
It's stated wrongly. The Collatz Conjecture is about the case where you triple an odd number and add one, that way you enter a loop if you get down to 1 (1 -> 4 -> 2 -> 1)
It isn't stated wrongly: 2n+1 get on, which means 3n+1 are on board
touche